A) \[2.0\times {{10}^{-4}}\]
B) \[4.0\times {{10}^{-3}}\]
C) \[8.0\times {{10}^{-12}}\]
D) \[3.2\times {{10}^{-11}}\]
Correct Answer: D
Solution :
\[{{K}_{sp}}\]for \[Ca{{F}_{2}}=4{{s}^{3}}\] \[=4\times {{[2\times {{10}^{-4}}]}^{3}}=3.2\times {{10}^{-11}}\].You need to login to perform this action.
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