A) \[8\times {{10}^{-24}}\]
B) \[16\times {{10}^{-24}}\]
C) \[1.6\times {{10}^{-18}}\]
D) \[16\times {{10}^{-18}}\]
Correct Answer: D
Solution :
\[{{K}_{sp}}={{[A{{g}^{+}}]}^{2}}[Cro_{4}^{-\,-}]={{[2S]}^{2}}[0.01]\] =\[4{{S}^{2}}[0.01]=4{{[2\times {{10}^{-8}}]}^{2}}\times 0.01\]\[=\,\,16\times {{10}^{-18}}\] .You need to login to perform this action.
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