A) \[4\times {{10}^{-10}}M\]
B) \[2\times {{10}^{-7}}M\]
C) \[4\times {{10}^{-6}}M\]
D) \[2\times {{10}^{-3}}M\]
Correct Answer: C
Solution :
\[BaS{{O}_{4}}\]⇌\[B{{a}^{2+}}+SO_{4}^{2-}\] \[{{K}_{sp}}={{S}^{2}}\Rightarrow S=\sqrt{{{K}_{sp}}}\];\[{{K}_{sp}}=[B{{a}^{2+}}]\times [SO_{4}^{2-}]\] \[4\times {{10}^{-10}}=[1\times {{10}^{-4}}]\times [SO_{4}^{2-}]\] \[[SO_{4}^{2-}]=\frac{4\times {{10}^{-10}}}{1\times {{10}^{-4}}}=4\times {{10}^{-6}}\].You need to login to perform this action.
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