A) \[{{10}^{-4}}M\]
B) \[{{10}^{-7}}M\]
C) \[{{10}^{-6}}M\]
D) \[{{10}^{-5}}M\]
Correct Answer: D
Solution :
\[[B]=\frac{{{K}_{sp}}AB}{[A]}=\frac{1\times {{10}^{-8}}}{{{10}^{-3}}}=1\times {{10}^{-5}}M\] Where ionic product > \[{{K}_{sp}},\,ppt\] formed \[\therefore \] 8 should be more then \[{{10}^{-5}}M\].You need to login to perform this action.
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