A) \[3.05\times {{10}^{-4}}\]
B) 10
C) \[6.1\times {{10}^{-4}}\]
D) \[9.3\times {{10}^{-8}}\]
Correct Answer: D
Solution :
\[\underset{S}{\mathop{CaC{{O}_{3}}}}\,\]⇌\[\underset{S}{\mathop{C{{a}^{++}}}}\,+\underset{S}{\mathop{CO_{3}^{-\,-}}}\,\] Solubility product of \[CaC{{O}_{3}}\] \[{{K}_{sp}}={{S}^{2}}\]; \[S=\sqrt{{{K}_{sp}}}\] It is a binary electrolyte. \[{{S}^{2}}={{K}_{sp}}\]; \[{{(3.05\times {{10}^{-4}})}^{2}}={{K}_{sp}}\];\[{{K}_{sp}}=9.3\times {{10}^{-8}}\]
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