A) \[{{10}^{-9}}M\]
B) \[{{10}^{-8}}M\]
C) \[{{10}^{-7}}M\]
D) \[{{10}^{-6}}M\]
Correct Answer: C
Solution :
\[{{K}_{sp}}\] of \[BaS{{O}_{4}}=1.5\times {{10}^{-9}}\]; \[B{{a}^{++}}=0.01M\] \[SO_{4}^{-\,-}=\frac{1.5\times {{10}^{-9}}}{0.01}=1.5\times {{10}^{-7}}\]You need to login to perform this action.
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