A) \[CaCr{{O}_{4}}\]
B) \[SrCr{{O}_{4}}\]
C) \[BaCr{{O}_{4}}\]
D) Mixture of A, B, C
Correct Answer: C
Solution :
When we added barium ion in chromate ion solution we obtained yellow ppt of \[BaCr{{O}_{4}}\]. \[BaC{{l}_{2}}+{{K}_{2}}Cr{{O}_{4}}\to \underset{\text{Yellow ppt}\text{.}}{\mathop{BaCr{{O}_{4}}}}\,\downarrow +\,2KCl\]You need to login to perform this action.
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