A) 1490, 1510
B) 1510, 1490
C) \[\frac{1}{1490},\frac{1}{1510}\]
D) \[\frac{1}{1510},\frac{1}{1490}\]
Correct Answer: A
Solution :
Here, \[{{f}_{c}}=1.5\,MHz=1500\,kHz,\]\[{{f}_{m}}==10\,kHz\] \ Low side band frequency \[={{f}_{c}}-{{f}_{m}}=1500\,kHz-10\,kHz=1490\,kHz\] Upper side band frequency \[={{f}_{c}}+{{f}_{m}}=1500\,kHz+10\,kHz=1510\,kHz\]You need to login to perform this action.
You will be redirected in
3 sec