JEE Main & Advanced Physics Communication System / संचार तंत्र Question Bank Communication

  • question_answer
    What should be the maximum acceptance angle at the aircore interface of an optical fibre if n1 and n2 are the refractive indices of the core and the cladding, respectively  [AIIMS 2005]

    A)            \[{{\sin }^{-1}}({{n}_{2}}/{{n}_{1}})\]                            

    B)            \[{{\sin }^{-1}}\sqrt{n_{1}^{2}-n_{2}^{2}}\]

    C)            \[\left[ {{\tan }^{-1}}\frac{{{n}_{2}}}{{{n}_{1}}} \right]\]     

    D)            \[\left[ {{\tan }^{-1}}\frac{{{n}_{1}}}{{{n}_{2}}} \right]\]

    Correct Answer: B

    Solution :

               Core of acceptance angle \[\theta ={{\sin }^{-1}}\sqrt{n_{1}^{2}-n_{2}^{2}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner