A) \[2\frac{1}{3}%\]
B) \[4\frac{1}{3}%\]
C) \[6\frac{1}{3}%\]
D) \[3\frac{1}{3}%\]
Correct Answer: D
Solution :
(d) \[A=P+\frac{\Pr \,t}{100}=12000\Rightarrow \frac{\Pr \,t}{100}=2000,\]where \[P=10000\] \[\therefore \]\[12000=10000\left( 1+\frac{6r}{100} \right)\Rightarrow \frac{6}{5}=1+\frac{6r}{100}\] \[\Rightarrow \]\[\frac{1}{5}=\frac{6r}{100}\Rightarrow r=\frac{100}{30%}=3\frac{1}{3}%\]You need to login to perform this action.
You will be redirected in
3 sec