A) \[6\frac{1}{4}%\]
B) \[12\frac{1}{2}%\]
C) \[25%\]
D) \[20%\]
Correct Answer: B
Solution :
(b) This is a TRIVIAL (Common sense) question. The statement of the problem itself signifies that a is \[=\frac{100}{900}\times 100%=\frac{1}{9}\times 100%=11\frac{1}{9}%\] more than b.You need to login to perform this action.
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