A) 2 : 3
B) 1 : 1
C) 3 : 4
D) 4 : 3
Correct Answer: D
Solution :
(d):5% of A+4% of B \[=\frac{5A}{100}+\frac{8B}{100}\] 6 % of A+8% of B \[=\frac{6A}{100}+\frac{8B}{100}\] Now \[\frac{5A+4B}{\cancel{100}}=\frac{2}{3}\left( \frac{6A+8B}{\cancel{100}} \right)\] \[\Rightarrow 3\left( 5A+4B \right)=2\left( 6A+8B \right)\] \[\Rightarrow 15A+12B=12A+16B\] \[\Rightarrow 3A=4B\Rightarrow \frac{A}{B}=4/3\].You need to login to perform this action.
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