A) \[AgN{{O}_{3}}\]
B) \[ZnS{{O}_{4}}\]
C) \[FeS{{O}_{4}}\]
D) All of these
Correct Answer: A
Solution :
\[Cu+2AgN{{O}_{3}}\to 2Ag+Cu{{(N{{O}_{3}})}_{2}}\] \[Cu+ZnS{{O}_{4}}\to \]no reaction \[Cu+FeS{{O}_{4}}\to \]no reaction \[\left. \begin{matrix} {{E}^{0}}Z{{n}^{+2}}/Zn=-0.76\,V \\ {{E}^{0}}C{{u}^{2+}}/Cu=+0.34\,V \\ {{E}^{0}}F{{e}^{2+}}/Fe=-0.40\,V \\ {{E}^{0}}A{{g}^{+}}/Ag=+0.80\,V \\ \end{matrix} \right\}\] As it is clear that reduction potential of copper is more than Zn and Fe. Hence it is unable to displace them from their salts.You need to login to perform this action.
You will be redirected in
3 sec