Column-I | Column-II |
(i) When number x is multiplied by 10 and then divided by 8, the result is 270. Then, x is | (p) 1632 |
(ii) There are 48 crates of apples. Each crate contains 34 apples. Number of apples altogether are | (q) 324 |
(iii) Subtract 3987 from the sum of 4687 and 28080. | (r) 216 |
(iv) The product of third multiple of 9 with 12 is | (s) 28780 |
A) \[(i)\to (p),(ii)\to (q),(iii)\to 9(r),(iv)\to (s)\]
B) \[(i)\to (r),(ii)\to (p),(iii)\to (s),(iv)\to (q)\]
C) \[(i)\to (r),(ii)\to (p),(iii)\to (q),(iv)\to (s)\]
D) \[(i)\to (r),(ii)\to (s),(iii)\to (p),(iv)\to (q)\]
Correct Answer: B
Solution :
(i) Let the number x be 216 (ii) Number of apples in 1 crate = 34 \[\therefore \] Number of apples in 48 crates \[=34\times 48=1632\] (iii) Sum of 4687 and 28080 \[\begin{align} & \,\,\,\,28080 \\ & \,\,\,\underline{+\,\,4687} \\ & =\underline{32767} \\ \end{align}\] Now, \[32767-3987=28780\] (iv) Third multiple of \[9=27\] \[\therefore \] Required product \[=\text{ }27\times 12=324\]You need to login to perform this action.
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