JEE Main & Advanced
Mathematics
Complex Numbers and Quadratic Equations
Question Bank
Condition for common roots, Quadratic expressions and Position of roots
question_answer
If \[x\] be real, the least value of \[{{x}^{2}}-6x+10\] is [Kurukshetra CEE 1998]
A)1
B)2
C)3
D)10
Correct Answer:
A
Solution :
If \[{{x}^{2}}-6x+10={{(x-3)}^{2}}+1\] For real x, least value of \[{{(x-3)}^{2}}+1\]is 1.