A) \[\frac{2}{15}\]
B) \[\frac{7}{15}\]
C) \[\frac{8}{15}\]
D) \[\frac{14}{15}\]
Correct Answer: C
Solution :
Let A be the event of selecting bag X, B be the event of selecting bag Y and E be the event of drawing a white ball, then \[P(A)=1/2,\,P(B)=1/2\], \[P(E/A)=2/5\] \[P(E/B)=4/6=2/3\]. \[P(E)=P(A)P(E/A)+P(B)P(E/B)=\frac{1}{2}\cdot \frac{2}{5}+\frac{1}{2}\cdot \frac{2}{3}=\frac{8}{15}\].You need to login to perform this action.
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