A) \[\frac{1}{2}\]
B) \[\frac{1}{4}\]
C) \[\frac{1}{3}\]
D) None of these
Correct Answer: C
Solution :
Let \[P(A)=\] probability of a boy in two children \[=\frac{3}{4}\] Because cases are \[BB,\,BG,\,GB,\,GG=4\] Favourable cases are \[BB,\,BG,\,GB=3\] The probability that the second child is also boy is \[P(A\cap B)=\frac{1}{4}\] We have to find \[P(B/A)=\frac{P(A\cap B)}{P(A)}=\frac{1/4}{3/4}=\frac{1}{3}.\]You need to login to perform this action.
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