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JEE Main & Advanced Physics Transmission of Heat Question Bank Conduction

  • question_answer
    The thickness of a metallic plate is 0.4 cm. The temperature between its two surfaces is \[{{20}^{o}}C\]. The quantity of heat flowing per second is 50 calories from \[5c{{m}^{2}}\] area. In CGS system, the coefficient of thermal conductivity will be

    A)            0.4 

    B)            0.6

    C)            0.2 

    D)            0.5

    Correct Answer: C

    Solution :

               \[\frac{Q}{t}=\frac{KA(\Delta \theta )}{l}\]Þ \[50=\frac{5\times 20\ K}{0.4}\Rightarrow K=\frac{1}{5}=0.2\]


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