A) \[{{1}^{o}}C\]
B) \[{{10}^{o}}C\]
C) \[{{100}^{o}}C\]
D) \[{{1000}^{o}}C\]
Correct Answer: C
Solution :
\[\Delta \theta =\frac{Q\times l}{KAt}=\frac{4000\times 0.1}{400\times {{10}^{-2}}}={{100}^{o}}C\]You need to login to perform this action.
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