JEE Main & Advanced Physics Transmission of Heat Question Bank Conduction

  • question_answer
    A heat flux of \[4000\ J/s\] is to be passed through a copper rod of length \[10\ cm\] and area of cross-section \[100\ c{{m}^{2}}\]. The thermal conductivity of copper is \[400\ W/m{{\ }^{o}}C\]. The two ends of this rod must be kept at a temperature difference of                                [MP PMT 1999]

    A)            \[{{1}^{o}}C\]                      

    B)            \[{{10}^{o}}C\]

    C)            \[{{100}^{o}}C\]                  

    D)            \[{{1000}^{o}}C\]

    Correct Answer: C

    Solution :

               \[\Delta \theta =\frac{Q\times l}{KAt}=\frac{4000\times 0.1}{400\times {{10}^{-2}}}={{100}^{o}}C\]


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