A) 0.23
B) 0.46
C) 0.115
D) 0.69
Correct Answer: A
Solution :
\[\frac{{{K}_{1}}}{{{K}_{2}}}=\frac{l_{1}^{2}}{l_{2}^{2}}\] \[\therefore \]\[{{K}_{2}}=\frac{{{K}_{1}}l_{2}^{2}}{l_{1}^{2}}=\frac{0.92\times {{(4.2)}^{2}}}{{{(8.4)}^{2}}}=0.23\]You need to login to perform this action.
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