A) \[{{75}^{o}}C\]
B) \[{{67}^{o}}C\]
C) \[{{33}^{o}}C\]
D) \[{{25}^{o}}C\]
Correct Answer: A
Solution :
Temperature of interface \[\theta =\frac{{{K}_{1}}{{\theta }_{1}}{{l}_{2}}+{{K}_{2}}{{\theta }_{2}}{{l}_{1}}}{{{K}_{1}}{{l}_{2}}+{{K}_{2}}{{l}_{1}}}\] It is given that \[{{K}_{Cu}}=9{{K}_{S}}.\] So if \[{{K}_{S}}={{K}_{1}}=K\] then \[{{K}_{Cu}}={{K}_{2}}=9K\] Þ q \[=\frac{9K\times 100\times 6+K\times 0\times 18}{9K\times 6+K\times 18}\]=\[\frac{5400K}{72K}=75{}^\circ C\]
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