JEE Main & Advanced Physics Transmission of Heat Question Bank Conduction

  • question_answer
    A slab consists of two parallel layers of two different materials of same thickness having thermal conductivities K1 and K2. The equivalent conductivity of the combination is  [BHU 2001]

    A)            \[{{K}_{1}}+{{K}_{2}}\]     

    B)            \[\frac{{{K}_{1}}+{{K}_{2}}}{2}\]

    C)            \[\frac{2{{K}_{1}}{{K}_{2}}}{{{K}_{1}}+{{K}_{2}}}\]  

    D)            \[\frac{{{K}_{1}}+{{K}_{2}}}{2{{K}_{1}}{{K}_{2}}}\]

    Correct Answer: B

    Solution :

                       In parallel combination equivalent conductivity            \[K=\frac{{{K}_{1}}{{A}_{1}}+{{K}_{2}}{{A}_{2}}}{{{A}_{1}}+{{A}_{2}}}=\frac{{{K}_{1}}+{{K}_{2}}}{2}\] (As \[{{A}_{1}}={{A}_{2}}\])


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