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JEE Main & Advanced Physics Transmission of Heat Question Bank Conduction

  • question_answer
    The heat is flowing through a rod of length 50 cm and area of cross-section \[5c{{m}^{2}}\]. Its ends are respectively at \[{{25}^{o}}C\] and \[{{125}^{o}}C\]. The coefficient of thermal conductivity of the material of the rod is 0.092 kcal/m×s×oC. The temperature gradient in the rod is                                      [MP PET 2002]

    A)            \[{{2}^{o}}C/cm\]              

    B)            \[{{2}^{o}}C/m\]

    C)            \[{{20}^{o}}C/cm\]            

    D)            \[{{20}^{o}}C/m\]

    Correct Answer: A

    Solution :

               Temperature gradient \[\frac{d\theta }{dx}=\frac{{{(125-25)}^{o}}C}{50\ cm}=2{}^\circ C/cm\]


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