A) 70 o C
B) 50 o C
C) 50 o C
D) 90 o C
Correct Answer: A
Solution :
Temperature of interface \[\theta =\frac{{{K}_{1}}{{\theta }_{1}}+{{K}_{2}}{{\theta }_{2}}}{{{K}_{1}}+{{K}_{2}}}\] It is given that \[\frac{{{K}_{1}}}{{{K}_{2}}}=\frac{5}{3}\] Þ \[{{K}_{1}}=5K\] and \[{{K}_{2}}=3K\] \[\theta =\frac{5K\times 100+3K\times 20}{5K+3K}\]\[=\frac{560K}{8K}\]=70°C
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