A) 25°C
B) 50°C
C) 75°C
D) 100°C
Correct Answer: A
Solution :
It is given that \[\frac{{{K}_{1}}}{{{K}_{2}}}=\frac{1}{3}\] Þ \[{{K}_{1}}=K\] then \[{{K}_{2}}=3K\] the temperature of the junction in contact \[\theta =\frac{{{K}_{1}}{{\theta }_{1}}+{{K}_{2}}{{\theta }_{2}}}{{{K}_{1}}+{{K}_{2}}}\]\[=\frac{1\times 100+3\times 0}{1+3}=\frac{100}{4}\]= 25°CYou need to login to perform this action.
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