A) 101.5
B) 139.5
C) 203.5
D) 279.5
Correct Answer: B
Solution :
\[{{\lambda }^{\,\infty }}\,BaC{{l}_{2}}=\frac{1}{2}{{\lambda }^{\,\,\infty }}B{{a}^{2+}}+\lambda {{\,}^{\infty }}C{{l}^{-}}\] \[=\frac{127}{2}+76=139.5\,\,oh{{m}^{-1}}\,\,c{{m}^{-1}}\,e{{q}^{-1}}\].You need to login to perform this action.
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