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JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Conductor and Conductance

  • question_answer
    If equivalent conductance of \[1M\] benzoic acid is \[12.8oh{{m}^{-1}}c{{m}^{2}}\] and if the conductance of benzoate ion and \[{{H}^{+}}\] ion are 42 and \[288.42\,oh{{m}^{-1}}c{{m}^{2}}\] respectively. its degree of dissociation is                                           [DPMT 2005]

    A)                 39%       

    B)                 3.9%

    C)                 0.35%   

    D)                 0.039%

    Correct Answer: B

    Solution :

               \[\Lambda _{m\,({{C}_{6}}{{H}_{5}}COOH)}^{o}=\Lambda _{\,({{C}_{6}}{{H}_{5}}CO{{O}^{-}})}^{o}+\Lambda _{({{H}^{+}})}^{o}\]                    \[=42+288.42=330.42\]                                 \[\alpha =\frac{\Lambda _{m}^{c}}{\Lambda _{m}^{o}}=\frac{12.8}{330.42}=3.9%\]


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