A) \[\Delta ABC\cong \Delta ADC\]
B) \[\Delta BCA=\Delta DCA\]
C) \[\Delta ADC=\Delta ABC\]
D) All of these
Correct Answer: D
Solution :
In \[\Delta ABC\] and \[\Delta ADC,\] we have AB = AD (given) CB = CD (given) AC = AC (common) \[\therefore \] \[\Delta ABC\cong \Delta ADC\] (By SSS) \[\therefore \] \[\angle ADC=\angle ABC\] and \[\angle BCA=\angle DCA\](By CPCT)You need to login to perform this action.
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