DIRECTION: Study the figure and information given below carefully and answer the following questions. |
CF and AE are equal perpendiculars on BD, BF = FE = ED. |
A) \[\Delta \,AED\]
B) \[\Delta \,BFC\]
C) \[\Delta \,CDF\]
D) \[\Delta \,BCD\]
Correct Answer: C
Solution :
In AABE and \[\Delta \,CDF\] AE = CF (given) \[\angle AEB=\angle CFD={{90}^{o}}\] (given) \[BF+FE=DE+EF\] \[\Rightarrow \] BE = DF \[\Rightarrow \]\[\Delta ABE\cong \Delta CDF\] (By SAS)You need to login to perform this action.
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