A) \[\frac{3i}{4}\]
B) \[\frac{11+10i}{17}\]
C) \[\frac{11-10i}{17}\]
D) \[\frac{2+3i}{4i}\]
Correct Answer: B
Solution :
\[\frac{2-3i}{4-i}=\frac{(2-3i)\,(4+i)}{(4+i)\,(4-i)}\]\[=\frac{8+3-12i+2i}{16+1}\]\[=\,\frac{11-10i}{17}\] Þ Conjugate \[=\frac{11+10i}{17}\].You need to login to perform this action.
You will be redirected in
3 sec