A) \[{{A}^{2}}+{{B}^{2}}\]
B) \[{{A}^{2}}-{{B}^{2}}\]
C) \[{{A}^{2}}\]
D) \[{{B}^{2}}\]
Correct Answer: A
Solution :
\[(a+ib)(c+id)(e+if)(g+ih)=A+iB\] .....(i) Þ \[(a-ib)(c-id)(e-if)(g-ih)=A-iB\] ......(ii) Multiplying (i) and (ii), we get \[({{a}^{2}}+{{b}^{2}})({{c}^{2}}+{{d}^{2}})({{e}^{2}}+{{f}^{2}})({{g}^{2}}+{{h}^{2}})={{A}^{2}}+{{B}^{2}}\]You need to login to perform this action.
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