A) 0
B) \[\pi /6\]
C) \[\pi /3\]
D) \[\pi /2\]
Correct Answer: D
Solution :
\[z=\frac{1+\sqrt{3}i}{\sqrt{3}-i}\]\[=\,\frac{1+\sqrt{3}i}{\sqrt{3}-i}\times \]\[\frac{\sqrt{3}+i}{\sqrt{3}+i}\] \[=\frac{\sqrt{3}+i+3i-\sqrt{3}}{3+1}\]=\[\frac{4i}{4}=i\] amp\[(z)=\,\pi /2\] \[[\because \,\tan \theta =b/a]\]You need to login to perform this action.
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