A) \[\pi \]
B) \[\pi /3\]
C) \[2\pi /3\]
D) \[\pi /4\]
Correct Answer: C
Solution :
\[z=\frac{-2}{1+\sqrt{3}i}\]=\[\frac{-2}{1+\sqrt{3}i}\times \frac{1-\sqrt{3}i}{1-\sqrt{3}i}\]\[=\frac{-2+2\sqrt{3}i}{1+3}\] \[\Rightarrow z=\frac{-1}{2}+\frac{\sqrt{3}}{2}i\]\[\Rightarrow \,arg\,(z)={{\tan }^{-1}}\left( -\frac{\sqrt{3}/2}{1/2} \right)=\frac{2\pi }{3}\].You need to login to perform this action.
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