JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Conservation of Energy and Momentum

  • question_answer
    A body of mass 2 kg is projected vertically upwards with a velocity of \[2\,m\,{{\sec }^{-1}}\]. The K.E. of the body just before striking the ground is                                       [EAMCET 1980]

    A)                 2 J          

    B)                 1 J

    C)                 4 J

    D)                 8 J

    Correct Answer: C

    Solution :

                        If particle is projected vertically upward with velocity of 2m/s then it returns with the same velocity.                 So its kinetic energy \[=\frac{1}{2}m{{v}^{2}}=\frac{1}{2}\times 2\times {{(2)}^{2}}=4\,J\]


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