A) 36
B) 72
C) 108
D) Data is incomplete
Correct Answer: A
Solution :
The bomb of mass 12kg divides into two masses m1 and m2 then \[{{m}_{1}}+{{m}_{2}}=12\] ?(i) and \[\frac{{{m}_{1}}}{{{m}_{2}}}=\frac{1}{3}\] ?(ii) by solving we get \[{{m}_{1}}=3kg\] and \[{{m}_{2}}=9kg\] Kinetic energy of smaller part = \[\frac{1}{2}{{m}_{1}}v_{1}^{2}=216J\] \ \[v_{1}^{2}=\frac{216\times 2}{3}\]Þ \[{{v}_{1}}=12m/s\] So its momentum = \[{{m}_{1}}{{v}_{1}}=3\times 12=36\ kg\text{-}\text{m}/s\] As both parts possess same momentum therefore momentum of each part is \[36\ kg\text{-}m/s\] The bomb of mass 12kg divides into two masses m1 and m2 then \[{{m}_{1}}+{{m}_{2}}=12\] ?(i) and \[\frac{{{m}_{1}}}{{{m}_{2}}}=\frac{1}{3}\] ?(ii) by solving we get \[{{m}_{1}}=3kg\] and \[{{m}_{2}}=9kg\] Kinetic energy of smaller part = \[\frac{1}{2}{{m}_{1}}v_{1}^{2}=216J\] \ \[v_{1}^{2}=\frac{216\times 2}{3}\]Þ \[{{v}_{1}}=12m/s\] So its momentum = \[{{m}_{1}}{{v}_{1}}=3\times 12=36\ kg\text{-}\text{m}/s\] As both parts possess same momentum therefore momentum of each part is \[36\ kg\text{-}m/s\]
You need to login to perform this action.
You will be redirected in
3 sec
