A) \[2.5\times {{10}^{4}}J\]
B) \[3.5\times {{10}^{4}}J\]
C) \[4.8\times {{10}^{4}}J\]
D) \[5.2\times {{10}^{4}}J\]
Correct Answer: C
Solution :
As the momentum of both fragments are equal therefore \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{m}_{2}}}{{{m}_{1}}}=\frac{3}{1}\]i.e. \[{{E}_{1}}=3{{E}_{2}}\] ?(i) According to problem \[{{E}_{1}}+{{E}_{2}}=6.4\times {{10}^{4}}J\] ?(i) By solving equation (i) and (ii) we get \[{{E}_{1}}=4.8\times {{10}^{4}}J\]and \[{{E}_{2}}=1.6\times {{10}^{4}}J\]You need to login to perform this action.
You will be redirected in
3 sec