A) \[({{h}_{1}}-{{h}_{2}})g\rho \]
B) \[({{h}_{1}}-{{h}_{2}})gA\rho \]
C) \[\frac{1}{2}{{({{h}_{1}}-{{h}_{2}})}^{2}}gA\rho \]
D) \[\frac{1}{4}{{({{h}_{1}}-{{h}_{2}})}^{2}}gA\rho \]
Correct Answer: C
Solution :
\[P=\sqrt{2mE}.\] If m is constant then \[\frac{{{P}_{2}}}{{{P}_{1}}}=\sqrt{\frac{{{E}_{2}}}{{{E}_{1}}}}=\sqrt{\frac{1.22E}{E}}\]Þ \[\frac{{{P}_{2}}}{{{P}_{1}}}=\sqrt{1.22}=1.1\] Þ\[{{P}_{2}}=1.1{{P}_{1}}\]Þ \[{{P}_{2}}={{P}_{1}}+0.1{{P}_{1}}={{P}_{1}}+10%\ \text{of }\ {{P}_{1}}\] So the momentum will increase by 10%
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