A) \[19.6Joule\]
B) \[4.9\,Joule\]
C) \[10\,Joule\]
D) \[9.8\,Joule\]
Correct Answer: D
Solution :
If there is no air drag then maximum height \[H=\frac{{{u}^{2}}}{2g}=\frac{14\times 14}{2\times 9.8}=10\,m\] But due to air drag ball reaches up to height 8m only. So loss in energy \[=mg(10-8)=0.5\times 9.8\times 2=9.8\,J\]
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