A) \[0.81\,kWh\]
B) \[0.90\,kWh\]
C) \[1.11kWh\]
D) \[0.71\,kWh\]
Correct Answer: A
Solution :
\[1\,kcal={{10}^{3}}\,Calorie=4200\,J\] \[=\frac{4200}{3.6\times {{10}^{6}}}{{K}_{w}}h\] \ \[700\,kcal=\frac{700\times 4200}{3.6\times {{10}^{6}}}kWh=0.81\,kWh\]
You need to login to perform this action.
You will be redirected in
3 sec
