A) 1 cm
B) 2 cm
C) 3 cm
D) 4 cm
Correct Answer: A
Solution :
For first condition Initial velocity = u, Final velocity = u/2, s = 3 cm From \[{{v}^{2}}={{u}^{2}}-2as\]Þ \[{{\left( \frac{u}{2} \right)}^{2}}={{u}^{2}}-2as\]Þ \[a=\frac{3{{u}^{2}}}{8s}\] Second condition Initial velocity = u/2, Final velocity = 0 From \[{{v}^{2}}={{u}^{2}}-2ax\]Þ\[0=\frac{{{u}^{2}}}{4}-2ax\] \ \[x=\frac{{{u}^{2}}}{4\times 2a}=\frac{{{u}^{2}}\times 8s}{4\times 2\times 3{{u}^{2}}}=s/3=1\,cm\]
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