A) 1 : 2
B) 1 : 4
C) \[1\,:\,\sqrt{2}\]
D) \[\sqrt{2}\,:\,1\]
Correct Answer: B
Solution :
\[P=\sqrt{2mE}.\] \[P\propto \sqrt{m}\]\ \[\frac{{{P}_{1}}}{{{P}_{2}}}=\sqrt{\frac{1}{16}}=\frac{1}{4}\]
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