A) n times
B) 2n times
C) \[\sqrt{n}\]times
D) \[{{n}^{2}}\] times
Correct Answer: D
Solution :
\[E=\frac{{{P}^{2}}}{2m}\] \ \[E\propto {{P}^{2}}\] i.e. if P is increased n times then E will increase n2 times.
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