JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Conservation of Energy and Momentum

  • question_answer
    A particle of mass m at rest is acted upon by a force F for a time t. Its Kinetic energy after an interval t is                 [Kerala PET 2002]

    A)                 \[\frac{{{F}^{2}}{{t}^{2}}}{m}\] 

    B)                 \[\frac{{{F}^{2}}{{t}^{2}}}{2m}\]

    C)                 \[\frac{{{F}^{2}}{{t}^{2}}}{3m}\]               

    D)                 \[\frac{F\,t}{2m}\]

    Correct Answer: B

    Solution :

                        Kinetic energy \[E=\frac{{{P}^{2}}}{2m}=\frac{{{(Ft)}^{2}}}{2m}\]\[=\frac{{{F}^{2}}{{t}^{2}}}{2m}\]           [As P = F t]


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