A) \[a\]
B) \[{{a}^{2}}\]
C) \[{{a}^{-2}}\]
D) \[{{a}^{0}}\]
Correct Answer: B
Solution :
Potential energy of spring = \[\frac{1}{2}K{{x}^{2}}\] \ \[PE\propto {{x}^{2}}\] Þ \[PE\propto {{a}^{2}}\]
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