A) 4 : 1
B) 1 : 1
C) 1 : 2
D) 1 : 4
Correct Answer: C
Solution :
\[p=\sqrt{2mE}\] \ \[P\propto \sqrt{m}\] Þ \[\frac{{{P}_{1}}}{{{P}_{2}}}=\sqrt{\frac{{{m}_{1}}}{{{m}_{2}}}}=\sqrt{\frac{m}{4m}}=\frac{1}{2}\]
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