JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Conservation of Energy and Momentum

  • question_answer
    A particle of mass \[{{m}_{1}}\] is moving with a velocity \[{{v}_{1}}\]and another particle of mass \[{{m}_{2}}\]is moving with a velocity \[{{v}_{2}}\]. Both of them have the same momentum but their different kinetic energies are \[{{E}_{1}}\]and \[{{E}_{2}}\]respectively. If \[{{m}_{1}}>{{m}_{2}}\] then                                            [CBSE PMT 2004]

    A)                 \[{{E}_{1}}<{{E}_{2}}\]  

    B)                 \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{m}_{1}}}{{{m}_{2}}}\]

    C)                    \[{{E}_{1}}>{{E}_{2}}\]

    D)                    \[{{E}_{1}}={{E}_{2}}\]

    Correct Answer: A

    Solution :

                        \[E=\frac{{{P}^{2}}}{2m}\] if P = constant then \[E\propto \frac{1}{m}\] According to problem \[{{m}_{1}}>{{m}_{2}}\] \ \[{{E}_{1}}<{{E}_{2}}\]


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