A) 1 : 2
B) 1 : 1
C) 4 : 1
D) 1 : 4
Correct Answer: D
Solution :
\[E=\frac{{{p}^{2}}}{2m}\] \ \[m\propto \frac{1}{E}\] (If momentum are constant) \[\frac{{{m}_{1}}}{{{m}_{2}}}=\frac{{{E}_{2}}}{{{E}_{1}}}=\frac{1}{4}\]You need to login to perform this action.
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