A) \[\sqrt{2}:1\]
B) \[1:4\]
C) \[1:2\]
D) \[1:\sqrt{2}\]
Correct Answer: C
Solution :
Kinetic energy\[=\frac{1}{2}m{{v}^{2}}\] As both balls are falling through same height therefore they possess same velocity. but \[KE\propto m\] (If v = constant) \ \[\frac{{{\left( KE \right)}_{1}}}{{{\left( KE \right)}_{2}}}=\frac{{{m}_{1}}}{{{m}_{2}}}=\frac{2}{4}=\frac{1}{2}\]
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