A) Proton
B) Electron
C) Deutron
D) \[\alpha \]-particles
Correct Answer: B
Solution :
\[E=\frac{{{P}^{2}}}{2m}\] \ \[E\propto \frac{1}{m}\] (If P = constant) i.e. the lightest particle will possess maximum kinetic energy and in the given option mass of electron is minimum.
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